Smartphone maker company Motorola will soon launch 'Motorola Razor 40 Ultra' in India. The company has claimed that it will be the thinnest flip phone in the world. Motorola has teased the smartphone on the official website and social media accounts.
In the teaser, the company has told that it will reveal all the specifications of the phone on June 22. However, many details about the specifications of the smartphone have been revealed in media reports. Let us know about the specifications of Motorola Razor 40 Ultra according to these reports.
Display: The company will offer a 6.69-inch foldable display with a 165Hz refresh rate in the Motorola Razor 40 Ultra, with peak brightness of 1400 nits and HDR10+ support. With this, a 3.6-inch cover display will be available in the phone with 144Hz refresh rate.
Hardware and Software: For performance, Qualcomm Snapdragon 8 Plus Gen 1 processor can be found in Motorola Razr 40 Ultra. Out-of-the-box Android 13 will be available in it.
Camera: Dual camera setup has been given on the phone rear panel for photography. This includes a 12MP primary camera and a 13MP ultra-wide lens. At the same time, a 32MP camera with punch hole design can be given for selfie and video calling.
Battery and Charging: For power backup, it has a 3,800 mAh battery with 30W wired and 5W wireless charging support.
Connectivity Option: For connectivity, the phone will get 5G, 4G, 3G, Wi-Fi 6, Bluetooth, GPS, NFC, USB Type C for charging with in-display fingerprint.
